Asked by Ceasar
Would you expect the molar solubility of KIO4 to be greater in a 0.20 M NaNO3 solution or a 0.20 M KNO3 solution? Justify your answer.
Answers
Answered by
DrBob222
The solubility of KIO4 is KIO4 ==> K+ + IO4^-
So Ksp = (K^+)(IO4^-)
You have the common ion effect if KNO3 is used and the addition of the K^+ from KNO3 will DECREASE the solubility of KIO4. So the solubility will be greater in a NaNO3 solution.
So Ksp = (K^+)(IO4^-)
You have the common ion effect if KNO3 is used and the addition of the K^+ from KNO3 will DECREASE the solubility of KIO4. So the solubility will be greater in a NaNO3 solution.
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