Asked by DICKSON
How many molecules of NH3 are produced from the reaction of 7 mols of Ca(OH)2 according to the following
(NH4)2SO4+Ca(OH)2=NH3+CaSO4+H2O
(NH4)2SO4+Ca(OH)2=NH3+CaSO4+H2O
Answers
Answered by
DrBob222
Balance the equation.
(NH4)2SO4 + Ca(OH)2 ==> 2NH3 + CaSO4 + 2H2O
From the equation, 1 mol Ca(OH)2 will produce 2 mols NH3; therefore, 7 mols Ca(OH)2 will produce 14 mols NH3.
1 mol NH3 contains 6.02E23 molecules NH3; therefore, 14 mols NH3 will produce 14*6E23 molecules NH3.
(NH4)2SO4 + Ca(OH)2 ==> 2NH3 + CaSO4 + 2H2O
From the equation, 1 mol Ca(OH)2 will produce 2 mols NH3; therefore, 7 mols Ca(OH)2 will produce 14 mols NH3.
1 mol NH3 contains 6.02E23 molecules NH3; therefore, 14 mols NH3 will produce 14*6E23 molecules NH3.
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