It must start with one of the 5 nonzero digits.
since 100 is divisible by 4, that means you only have to make sure that the last two digits are divisible by 4. There are 25 multiples of 4 less than 100.
So, there are 5 * 6^3 * 25 = 27000 different possibilities
How many six digit can be formed using the digits 0, 1, 2, 3, 4, 5 which are divisible by 4 ?
1 answer