H3PO4 + 3NaOH ==> Na3PO4 + 3H2O
How many mols in 57 mg of P. Mols = grams/atomic mass = 0.057/approx 31 but you need to redo that and all calculations that follow. I've just estimated all calculations. mols P = 0.00184 mols. That's also 0.00184 mols H3PO4. Now convert mols H3PO4 to mols NaOH.
That's 0.00184 mols H3PO4 x (3 mols NaOH/1 mol H3PO4) = estimated 0.0055 mols NaOH.
Then mols NaOH = M x L = 0.0055 = M x L. You know M from the problem of the NaOH, substitute and solve for L, then convert to mL. Post your work if you get stuck.
One 240. mL serving of ChemCola™ contains 57.0 mg phosphorus (which is found in the phosphoric acid, H3PO4, in ChemCola). What volume (in mL) of 0.0950 M NaOH is needed to neutralize the H3PO4 in one serving of ChemCola™?
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