Asked by Leah
If we want to prepare 125 mL of a 1.245 M aqueous KCl solution, how many grams of KCl (rounded with correct number of significant figures) would we need to put in the solution?
Answers
Answered by
R_scott
.125 L * 1.245 M = ? mol
look up KCl molar mass and multiply by result of 1st calculation
3 sig fig in answer
look up KCl molar mass and multiply by result of 1st calculation
3 sig fig in answer
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