Question
In a first-order decomposition reaction, 50.0% of a compound decomposes in 19.5 min.
(a) What is the rate constant of the reaction? (round to four decimal places)
k = .03554 min−1
(b) How long does it take for 82.0% of the compound to decompose? (round to one decimal place)
t = ? min
(a) What is the rate constant of the reaction? (round to four decimal places)
k = .03554 min−1
(b) How long does it take for 82.0% of the compound to decompose? (round to one decimal place)
t = ? min
Answers
In a first-order decomposition reaction, 50.0% of a compound decomposes in 19.5 min.
(a) What is the rate constant of the reaction? (round to four decimal places)
k = .03554 min−1
<b>That's right but didn't you round to 5 decimal places? four significant figures. </b>
(b) How long does it take for 82.0% of the compound to decompose? (round to one decimal place)
t = ? min
<b>ln(No/N) = kt
No = 100% to start
N = 18% (100% - 82% = 18%)
k = from above
Solve for t in minutes. Post your work if you get stuck.
(a) What is the rate constant of the reaction? (round to four decimal places)
k = .03554 min−1
<b>That's right but didn't you round to 5 decimal places? four significant figures. </b>
(b) How long does it take for 82.0% of the compound to decompose? (round to one decimal place)
t = ? min
<b>ln(No/N) = kt
No = 100% to start
N = 18% (100% - 82% = 18%)
k = from above
Solve for t in minutes. Post your work if you get stuck.
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