Asked by janel
how do you graph 3x-y=5?
Answers
Answered by
Bob
First rearrange the equation into
Y=mx+b form. where m represents the slope & y represents the Y intercept. The X & Y represent the two coordinates that you are solving for.
When you rearrange it into y=mx+b form then the equation should read y=3x-5. 3 is your slope and -5 is your y-intercept. So first you start of with the y-intercept and you graph it at -5. so the coordinate will be (0,-5). then the slope as you know is 3x which basically means the slope is 3 over 1( this is because any whole number is basically the whole number over 1). 3 is your rise and 1 is your run. So from -5 you go up 3(rise) and right 1(run). once you get 2 points on the graph, just draw a straight line through them and you have your line.
Y=mx+b form. where m represents the slope & y represents the Y intercept. The X & Y represent the two coordinates that you are solving for.
When you rearrange it into y=mx+b form then the equation should read y=3x-5. 3 is your slope and -5 is your y-intercept. So first you start of with the y-intercept and you graph it at -5. so the coordinate will be (0,-5). then the slope as you know is 3x which basically means the slope is 3 over 1( this is because any whole number is basically the whole number over 1). 3 is your rise and 1 is your run. So from -5 you go up 3(rise) and right 1(run). once you get 2 points on the graph, just draw a straight line through them and you have your line.
Answered by
Limaris
thanks bob!!!!!
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