Question

When a boy is sitting 1 meter from the center of a see-saw, another boy must sit on the
opposite side 0.5 meter farther from the center compared to the first boy to maintain balance.
When the first boy carries an additional weight of 10 kg and sits 1.5 meters from the center, the
second boy must now move to 3 meters from the center to maintain balance. What is the weight
of the heavier boy?

Answer 1

If the weights are x and y, with x > y, then to balance things, we need
x(1) = y(1.5)
(x+10)(1.5) = y(3)
So now just solve for x