Question
How many joules of energy is required to bring a five-pound (1 pound = 454) bag of ice from its freezer temperature at -20.0°C up to 0°C? The specific heat of ice is 2.10 J/g×°C.
Answers
DrBob222
q = m*c*dT
q = 454 g x (2.10 J/g*C) x (20) = ? Joules.
q = 454 g x (2.10 J/g*C) x (20) = ? Joules.