Asked by Anonymous
If θ is an angle in standard position and its terminal side passes through the point (-1,3), find the exact value of \sec\thetasecθ in simplest radical form.
Answers
Answered by
Reiny
From the given point (-1,3) we know
x = -1, y = 3 and the point in in quadrant II
r^2 = (-1)^2 + 3^2 = 10
r = √10
secθ = r/x = -√10/1 = -√10
You must memorize all 6 trig ratios in terms of x, y, and r
e.g. tanθ = y/x
etc
x = -1, y = 3 and the point in in quadrant II
r^2 = (-1)^2 + 3^2 = 10
r = √10
secθ = r/x = -√10/1 = -√10
You must memorize all 6 trig ratios in terms of x, y, and r
e.g. tanθ = y/x
etc
Answered by
jandel
If θ is an angle in standard position and its terminal side passes through the point (1,-3), find the exact value of \tan\thetatanθ in simplest radical form
Answered by
jandel
On the axes below, make an appropriate scale and graph exactly one cycle of the trigonometric function y=3\cos 7xy=3cos7x.
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