Asked by Jeremy
The largest ship in Christopher Columbus' "fleet" was the Santa Maria, which displaced about 100 tons
(1 ton = 2,000 pounds) of seawater when fully loaded. Assuming the average density of seawater surrounding
the ship was 1.024 g mL-1, calculate the total volume of seawater (in m3) displaced by the ship's hull.
(1 ton = 2,000 pounds) of seawater when fully loaded. Assuming the average density of seawater surrounding
the ship was 1.024 g mL-1, calculate the total volume of seawater (in m3) displaced by the ship's hull.
Answers
Answered by
R_scott
1.024 g/cm^3 = 1.024 kg/dm^3 = 1024 kg/m^3
1 lb = .4536 kg
find kg in 100 tons (200000 lb)
divide by sea water density to find m^3
"about 100 tons" means an answer with one significant figure
1 lb = .4536 kg
find kg in 100 tons (200000 lb)
divide by sea water density to find m^3
"about 100 tons" means an answer with one significant figure
Answered by
oobleck
volume * density = mass = weight/9.81
so,
v * 1.024g/mL * 10^6ml/m^3 * 1kg/1000g = 100ton * 2000lb/ton * 1kg/2.2lb
v * 1.024*10^3 kg/m^3 = 2*10^5/2.2 kg
v = 88.778 m^3
so,
v * 1.024g/mL * 10^6ml/m^3 * 1kg/1000g = 100ton * 2000lb/ton * 1kg/2.2lb
v * 1.024*10^3 kg/m^3 = 2*10^5/2.2 kg
v = 88.778 m^3
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