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Asked by miya

factor.
x^4-81=0

*difference of squares not sure where to start
5 years ago

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Answered by oobleck
start by recalling that
a^2 - b^2 = (a-b)(a+b) and do it twice in this case
x^4 - 81
= (x^2-9)(x^2+9)
= (x-3)(x+3)(x^2+9)
5 years ago
Answered by miya
ty!!
5 years ago
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factor.
x^4-81=0

*difference of squares not sure where to start

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