Asked by line
1
Esteban drew Triangle JKL on a coordinate plane with J (−3,5), K (−1,−4), and L (2,4). Then he drew J'K'L', the results of the dilation were (x, y) --> (
\frac{2}{3}
3
2
x,
\frac{2}{3}
3
2
y) What are the coordinates of J'?
Esteban drew Triangle JKL on a coordinate plane with J (−3,5), K (−1,−4), and L (2,4). Then he drew J'K'L', the results of the dilation were (x, y) --> (
\frac{2}{3}
3
2
x,
\frac{2}{3}
3
2
y) What are the coordinates of J'?
Answers
Answered by
oobleck
assuming you meant (x,y)→(2/3 x, 2/3 y) then
(-3,5)→(-2 , 10/3)
If not, then maybe you can type it in a more readable format.
(-3,5)→(-2 , 10/3)
If not, then maybe you can type it in a more readable format.
Answered by
math god 😩🤌
(-2 1/3, 3 1/3)
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