Question
Disprove the following statements using counterexample.
(a) |x| > 0
(b)√x2 = x
(c)√x2+4 = x+ 2
(d) x2 > x
(e) x ≤ x2
(a) |x| > 0
(b)√x2 = x
(c)√x2+4 = x+ 2
(d) x2 > x
(e) x ≤ x2
Answers
oobleck
|0| = 0
√x^2| = |x|. √(-2)^2 = √4 = 2
√(a^2 + b^2) ≠ a+b since (a+b)^2 = a^2+2ab+b^2
Why don't you try the others?
√x^2| = |x|. √(-2)^2 = √4 = 2
√(a^2 + b^2) ≠ a+b since (a+b)^2 = a^2+2ab+b^2
Why don't you try the others?