Asked by erah
                Find the length of a side of a square if its area is 9ײ+30×+25.
            
            
        Answers
                    Answered by
            Reiny
            
    area = 9x²+30x+25
side = √(9x²+30x+25)
= √(3x+5)^2
= 3x+5, where x > -5/3
    
side = √(9x²+30x+25)
= √(3x+5)^2
= 3x+5, where x > -5/3
                    Answered by
            oobleck
            
    Since all we know is that 3x+5 > 0, maybe we should consider that
√(3x+5)^2 = |3x+5|
doesn't really matter what x is.
    
√(3x+5)^2 = |3x+5|
doesn't really matter what x is.
                    Answered by
            Ashley 
            
    Find the length of a side (s)of a square if it's area (a) is 9ײ+30 ×+25
    
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