q↔p=q+4p−5
so ...
−3↔13 = -3 + 4(13) - 5 = 44
1↔6 = 1 + 4(6) - 5 = 20
..... do the third one the same way, then write them in the order of the results
Hello there Can someone check my answer and explain it because I'm confused and took my best guess!
An operation ↔ is defined by q↔p=q+4p−5. Order the value of the following non-standard operations from least to greatest. −3↔13, 1↔6, 3↔4
A.−3↔13, 3↔4, 1↔6
B.3↔4, −3↔13, 1↔6
C.3↔4, 1↔6, −3↔13
D.−3↔13, 1↔6, 3↔4**** Thank you so much!
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