Asked by sami
What are the possible solutions of 2 logbase2 a= 10 - 2 logbase2 b, where a and b are integers
Answers
Answered by
oobleck
assuming logs base 2, you have
2loga = 10 - 2logb
loga+logb = 5
ab = 2^5 = 32
So a and b must be factors of 32. What are the possibilities?
2loga = 10 - 2logb
loga+logb = 5
ab = 2^5 = 32
So a and b must be factors of 32. What are the possibilities?
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