Question
1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).
What was the temperature of the iron before it was heated?
55 °C
35 °C
20 °C
45 °C
Not sure how to solve this problem, can anyone walk me through it?
What was the temperature of the iron before it was heated?
55 °C
35 °C
20 °C
45 °C
Not sure how to solve this problem, can anyone walk me through it?
Answers
anon
Never mind- I figured it out.
The answer is 45
The answer is 45
DrBob222
q = mass x specific heat Fe x (Tfinal-Tinitial)\
1125 J = 250 x 0.45 J/g*C x (55 - Tinitial)
Solve for Tinitial
Post your work if you get stuck.
1125 J = 250 x 0.45 J/g*C x (55 - Tinitial)
Solve for Tinitial
Post your work if you get stuck.