Question

1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).

What was the temperature of the iron before it was heated?
55 °C

35 °C

20 °C

45 °C

Not sure how to solve this problem, can anyone walk me through it?

Answer 1

Never mind- I figured it out.
The answer is 45

Answer 2

q = mass x specific heat Fe x (Tfinal-Tinitial)\
1125 J = 250 x 0.45 J/g*C x (55 - Tinitial)
Solve for Tinitial
Post your work if you get stuck.