Asked by Johnwesley

The 19th and 22nd term of an AP are 29 and 55 respectively. find the sum of the 60th term
Answered by oobleck
the 19th and 22nd terms differ by 3d.
So, d=(55-29)/3 = 8
Now you can find a
Not sure what <u>the sum of the 60th term</u> means, but the sum of the first 60 terms is
s = 60/2 (2a+59d)
Answered by Reiny
a + 18d = 29
a + 21d =55
subtract:
3d = 26
d = 26/3
a + 18(26/3) = 29
a = -127

"find the sum of the 60th term" makes no sense
Do you want the 60th term of the sum of the first 60 terms?

either way, just plug in the values of a and d into the formulas
Answered by oobleck
go with Reiny. I assumed an integer value for d, and missed the fact that 55-29=26, not 24.
Answered by Bbbbbmm be kcb
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Answered by Nic kol
26
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