Question
Write an equation for a hyperbola with foci at (–2, –2) and (8, –2), and asymptote with slope 4/3
Answers
the center is midway between the foci, at (3,-2) and the axis is horizontal, so the equation is
(x-3)^2/a^2 - (y+2)^2/b^2 = 1
So now use the asymptotes to determine a and b.
(x-3)^2/a^2 - (y+2)^2/b^2 = 1
So now use the asymptotes to determine a and b.
(x-3)
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