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If the distance from the center of a merry-go-round to the edge is 1.2m, what centripetal acceleration does a passenger experience when the merry go round rotates with a frequency of 0.08 hz?
5 years ago

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Centripetal acceleration = (2π x 0.08 hz)^2 x 1.2m
= 0.0048 m/s^2
2 years ago

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