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cos(t)/(5sin(t)+8)^2the answer i got was: xcos(t)/(5sin(t)+8)^2 this is not right when i put it in what did i do wrong?
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antiderivativef''=3x+5sin(x) f(0)=4 f'(0)=4 Find f(x) I got (1/2)x^3-5sin(x)+(15/2)x+(7/2), but it was wrong
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