acceleration=change in velocty/time= 114e3/(7*60)(3600) m/s^2
KE=1/2 m v^2=1/2 m (114e3/(7*60))
A motorcar with a mass of 1.3 tons accelerates uniformly from rest up an incline 4% and reaches a speed of 114km/h after 7 minutes. Calculate:
1.The acceleration of a motorcar.
2.the kinetic energy that a motorcar possesses after 7 minutes.
3. The gain in potential energy.
2 answers
?? I see that v = 114E3/3600 = 31.667 m/s for (b)
(c) PE = mgh = mg*(1/2 at^2)*sin(arctan(0.04))
(c) PE = mgh = mg*(1/2 at^2)*sin(arctan(0.04))
1 answer