Asked by hi
Find a constant A so that the roots of y=f(Ax) are {0,±10}.
Answers
Answered by
oobleck
there must be more to this than you are saying.
let A=1
f(Ax) = (Ax)(Ax-10)(Ax+10) = x(x-10)(x+10) = x^3-100x
so what makes finding A any work at all?
let A=1
f(Ax) = (Ax)(Ax-10)(Ax+10) = x(x-10)(x+10) = x^3-100x
so what makes finding A any work at all?
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