Asked by Alysha

Given 3 (square root 2m - n) = k
Express m in terms of k and n
Answered by oobleck
3√(3m-n) = k
9(3m-9) = k^2
3m-9 = k^2/9
3m = k^2/9 + 9
m = k^2/27 + 3
Answered by oobleck
oops. lost the n
3m-n = k^2/9
3m = k^2/9 + n
m = k^2/27 + n/3
or m = (k^2 + 9n)/27
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