Asked by lucy
The ratio of the 6th to the 2nd term of geometric sequence is 256.If the 3rd term of this sequence is 32.Determine the first and the third term.
Answers
Answered by
oobleck
(a+5d)/(a+d) = 256
a+2d = 32
Now solve for a
Not sure what you want when you say
the 3rd term ... is 32
Determine ... the 3rd term.
a+2d = 32
Now solve for a
Not sure what you want when you say
the 3rd term ... is 32
Determine ... the 3rd term.
Answered by
Reiny
ar^5/ar = 256
r^4 = 256
r = ± 4
ar^2 = 32
16a = 32
a = 2
1st term = 2
3rd term = ar^2 = 2(16) = 32
r^4 = 256
r = ± 4
ar^2 = 32
16a = 32
a = 2
1st term = 2
3rd term = ar^2 = 2(16) = 32
Answered by
oobleck
Oops. Go with Reiny.
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