Asked by Anna
A box weighing 415 N is hanging from two chains attached to an overhead bean at angles of 56 degrees and 49 degree. Find the magnitude of the tension in each chain algebraically.
Answers
Answered by
Reiny
After sketching a "position diagram", that is, a diagram showing the actual situation,
I made a vector diagram with a vertical side labelled 415 N, the side opposite the angle of 41°
as T1, and the side opposite the 34° angle as T2. The 3rd angle would be 105°
by the sine law:
T1/sin41 = 415/sin105
T1 = 415sin41/sin105 = ...
find T2 in the same way
I made a vector diagram with a vertical side labelled 415 N, the side opposite the angle of 41°
as T1, and the side opposite the 34° angle as T2. The 3rd angle would be 105°
by the sine law:
T1/sin41 = 415/sin105
T1 = 415sin41/sin105 = ...
find T2 in the same way
Answered by
Keisha Mitchell
Did you find the answer?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.