Asked by Olayiwola Damilare Samuel
4x³+2x²-3x+1/(2x+1)(x-3)
Answers
Answered by
oobleck
what about it? The numerator has no factors in common with the denominator.
(4x^3+2x^2-3x+1)/((2x+1)(x-3)) = 2x+6 + (33x+19)/((2x+1)(x-3))
or, as partial fractions,
2x+6 + (118/7)/(x-3) + (-5/7)/(2x+1)
(4x^3+2x^2-3x+1)/((2x+1)(x-3)) = 2x+6 + (33x+19)/((2x+1)(x-3))
or, as partial fractions,
2x+6 + (118/7)/(x-3) + (-5/7)/(2x+1)
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