You can play around with Z table stuff at
http://davidmlane.com/hyperstat/z_table.html
Maria handed in her final data management
project last week. The class mean was 83%
with a standard deviation of 8. If Maria’s
mark produced a z-score of 1.09, what was
her grade?
4 answers
I have tried but could not get through ,,,, any hint
Thx
Thx
well, yeah. Her score was 1.09 STD above the mean, so
83 + 1.09*8 = 91.72
83 + 1.09*8 = 91.72
Thx
1 answer