Question

Factorise a^3+b^3+c(a^2+b^2-ab)

Answer 1

a^3+b^3+c(a^2+b^2-ab)

a^3 + b^3 = (a+b)(a^2 - ab + b^2)

so a^3+b^3+c(a^2+b^2-ab)
= (a+b)(a^2 - ab + b^2) + c(a^2 + b^2 - ab)
= (a^2 - ab + b^2)(a+b+c)