Question
A train is going at 1/3 of its usual speed and it takes an extra 30 minutes to reach its destination. Find its usual time to cover the same distance.
Answers
Not enough information:
e.g. suppose the distance is 90 km
and the usual speed is x km/h
then 90/(x/3) - 90/x = 1/2
(270-90)/x = 1/2 ----> x = 360 km/h
but suppose the distance is 60 km
then 60/(x/3) - 60/x = 1/2
(180-60)/x = 1/2 ---> x = 240 km/h
So the speed depends on the distance, and we are not given that
e.g. suppose the distance is 90 km
and the usual speed is x km/h
then 90/(x/3) - 90/x = 1/2
(270-90)/x = 1/2 ----> x = 360 km/h
but suppose the distance is 60 km
then 60/(x/3) - 60/x = 1/2
(180-60)/x = 1/2 ---> x = 240 km/h
So the speed depends on the distance, and we are not given that
I wasn't given the distance, but isn't there any way to solve it?
pop
so the formula is time = distance / speed
im sorry i checked again
its not letting me type anym
its not letting me type anym
isearch mo kaya
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