Asked by Ben

Br2(aq) + 2 KI(aq) ==> 2 KBr(aq) + I2(s)

What is oxidized and what is reduced in this reaction?
Answered by DrBob222
Assign oxidation numbers and you will know.
Br2(aq) + 2 KI(aq) ==> 2 KBr(aq) + I2(s)
Br2 is zero for each on the left to 2- on the right.
2I is 2- on the left to zero on the right.
Oxidation is the loss of electrons.
Reduction is the gain of electrons.
Answered by bobpursley
Bromine oxidiation number decreases (gains electron), Iodine loses an electron (loxidation number increases) https://qph.fs.quoracdn.net/main-qimg-c4dec6c49e9a1e0f1733c33ed5ec766c
Answered by Matilda
oxidation-reduction 2KBr+I2
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