log y= log(10xn)
you claim n is the power.
Did you mean n is the exponent?
Did mean:
log y= log(10x^n) ?
in that case, "antilog" both sides
y = 10x^n
x^n = y/10
log both sides
log x^n = log(y/10)
n logx = logy - log10
n = (logy - 1)/logx
Given that log y= log(10xn), make n the subject
NOTE: n is the power
3 answers
Thanks but I just can't understand anything from what uve done
I just used the fundamental rules of logarithm.
If you are studying logs, then you must know those.
If you are studying logs, then you must know those.