Sorry. If PR=19 and circle P touches the bowl, then the radius of the bowl must be 19+19 = 38
But, by the same token, it must also be 16+16 if QR=16
Two solid spherical balls with centres P and Q touch each other. The balls lie inside and in contact with a hemispherical bowl of center R. Given that PQ=13 cm, QR=16cm and PR=19cm, calculate the radii of the bowl and the two spherical balls
3 answers
Sorry - I misread the conditions. Suppose the radius of ball P is r.
Then the radius of ball R is 13-r.
Two radii RP and RQ both touch circle R.
So, R = 19+r = 16+(13-r)
r = 5
so R = 19+5 = 16+8 = 24
Then the radius of ball R is 13-r.
Two radii RP and RQ both touch circle R.
So, R = 19+r = 16+(13-r)
r = 5
so R = 19+5 = 16+8 = 24
Extra credit.
If Q is at (0,0) and R is at (0,16), where is P?
If Q is at (0,0) and R is at (0,16), where is P?
1 answer