Asked by Pearl

A man walks five miles due east and then three miles in a direction 60° north of east .calculate the displacement of the man.

Answers

Answered by Reiny
I made a sketch and got triangle ABC, with angle B = 120°, AB = 5, and BC = 3

looks like a normal cosine law problem
AC^2 = 5^2 + 3^2 - 2(5)(3)cos120°
....

then use the sine law to find angle A
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