Question

A battery of three cells in series, each of e.m.f 2V and internal resistance 0.5 Ω is connected to a 2 Ω resistor in series with a parallel combination of two 3 Ω resistor. Draw the circuit diagram and calculate:
1) the effective external resistance
2) the current in the circuit
3) the lost volts in the battery
4) the current in one of the 3 Ω resistors.
the two 3Ω resistors in parallel have an equivalent resistnce of 1.5Ω
So,
#1. 2 + 1.5 = 3.5Ω external R
See what you can do with that. It should not be too hard now.

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