Asked by idkhowtodomath
Given that (24z^3)^2/27x12z = 2^a 3^b z^c ,evaluate a,b and c.
Answers
Answered by
oobleck
is that
(24z^3)^2/27 * 12z
or
(24z^3)^2/(27 * 12z)
If the latter, then that is
(24^2 z^6)/(27 * 12 z)
= (8^2*3^2)/(3^3*2^2*3) * z^6/z
= (2^6 3^2)/(2^2 3^4) z^5
now finish it off
(24z^3)^2/27 * 12z
or
(24z^3)^2/(27 * 12z)
If the latter, then that is
(24^2 z^6)/(27 * 12 z)
= (8^2*3^2)/(3^3*2^2*3) * z^6/z
= (2^6 3^2)/(2^2 3^4) z^5
now finish it off
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.