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Asked by Chauncey Rosie

Solve for the interval 0<= theta<=2 pi; ; cos theta * sin theta - 1/2 * sin theta = 0
5 years ago

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Answered by oobleck
cosθ sinθ - 1/2 sinθ = 0
sinθ (cosθ - 1/2) = 0
so,
sinθ = 0
or
cosθ = 1/2
So where does that happen?
5 years ago
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Solve for the interval 0<= theta<=2 pi; ; cos theta * sin theta - 1/2 * sin theta = 0

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