How many lines through the origin make angles of 60degree with both the +y and +z axes ? What angle do they make with the +x axis ?

User Icon for oobleck oobleck answered
4 years ago

As usual, google can provide several discussions of the topic.

User Icon for Reiny Reiny answered
4 years ago

Let A, B, and C be the direction angles that our line makes with the x, the y, and the z axes respectively.

We know cos^2 A + cos^2 B + cos^2 C = 1
we are told that the line makes and angle of 60° with both the y and the z axes, and cos 60° = 1/2
so, cos^2 A + 1/4 + 1/4 = 1
cos^2 A = 1/2
cos A = 1/√2 or √2/2
then A = ± 45° , but -45° is coterminal with 315°
so the angle with the x-axis could be 45° or 315°

so our line could have terminal points of (1/2, 1/2, ±√2/2) or (1, 1, ±√2)
how many lines would that represent?

User Icon for Anonymous Anonymous answered
4 years ago

Reiny can you explain how you get (1, 1, ±√2). I don't understand how you get the terminal points in this order (1/2, 1/2, ±√2/2). If ( cos^2(A,cos^2(60),cos^(60)),should the terminal points be ( ±√2,1/2,1/2)?

User Icon for Reiny Reiny answered
4 years ago

You are right, I wasn't watching the order, and it was the angle with the x-axis that we didn't have.

User Icon for Anonymous Anonymous answered
4 years ago

Thank, So for (1/2, 1/2, ±√2/2) or (1, 1, ±√2), you just drop the denominator 2 because they all have a denominator of 2 and you get (±√2,1, 1 ). Is that right?

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the number of lines through the origin that make angles of 60 degrees with both the +y and +z axes, we can visualize a 3-dimensional coordinate system.

First, let's consider the +y axis. Any line passing through the origin and making an angle of 60 degrees with the +y axis will lie in a plane perpendicular to the +y axis. This plane can be represented by a line passing through the origin in the +x and +z directions.

Similarly, for the +z axis, any line passing through the origin and making an angle of 60 degrees with the +z axis will lie in a plane perpendicular to the +z axis. This plane can be represented by a line passing through the origin in the +x and +y directions.

To find the lines that satisfy both conditions, we need to find the intersection of these two planes. Since both planes share the same line passing through the origin in the +x direction, the intersection line will also lie along this common line.

Therefore, there is only one line that passes through the origin and makes angles of 60 degrees with both the +y and +z axes.

Now, let's find the angle this line makes with the +x axis. Since the line lies in the plane formed by the +x and +y axes, its projection onto the +xy plane will be perpendicular to the +x axis. Hence, the angle it makes with the +x axis is 90 degrees.

In summary:
- There is only one line passing through the origin that makes angles of 60 degrees with both the +y and +z axes.
- This line makes an angle of 90 degrees with the +x axis.