2NaHCO3 + H2SO4 ==> Na2SO4 + 2H2O + 2CO2
mols H2SO4 spilled = M x L = 9.0 x 2.0 = 18
From the equation, 2 mols NaHCO3 are needed for each mol H2SO4 so you will need 36 mols NaHCO3.
M NaHCO3 = mols/L. You know M and mols, solve for L.
Post your work if you get stuck.
Sodium bicarbonate is sometimes used to neutralize acid spills. If 2.0 L of 9.0 M H2SO4 is spilled, what mass of sodium bicarbonate (NaHCO3) is required to neutralize all the H2SO4?
1 answer