Asked by Anonymous
Find the vector projection of the vector 6i+3j+2k onto thevector 3i-2j+4k.
Answers
Answered by
oobleck
The projection of u onto v is u•v * v/|v|
So in this case, that would be
(6*3 + 3(-2) + 2*4)/√(3^2+2^2+4^2) = 20/√29 * 3i-2j+4k
So in this case, that would be
(6*3 + 3(-2) + 2*4)/√(3^2+2^2+4^2) = 20/√29 * 3i-2j+4k
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