Asked by frell
A camper does 7.4 x 102 J of work in lifting a pail filled with water 3.4 m vertically up a well at a constant speed.
a)What force is exerted by the camper on the pail of water?
b)What is the mass of water in the pail?
a)What force is exerted by the camper on the pail of water?
b)What is the mass of water in the pail?
Answers
Answered by
John
Work = force times distance
7.4 x 10^2 J = force x 3.4
divide by 3.4 to get the force in newtons.
Force = mass times gravity g= 9.8 m/sec^2
Divide your answer in part a by 9.8 to get the mass.
7.4 x 10^2 J = force x 3.4
divide by 3.4 to get the force in newtons.
Force = mass times gravity g= 9.8 m/sec^2
Divide your answer in part a by 9.8 to get the mass.
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