Question

A camper does 7.4 x 102 J of work in lifting a pail filled with water 3.4 m vertically up a well at a constant speed.
a)What force is exerted by the camper on the pail of water?
b)What is the mass of water in the pail?

Answer 1

Work = force times distance
7.4 x 10^2 J = force x 3.4
divide by 3.4 to get the force in newtons.

Force = mass times gravity g= 9.8 m/sec^2
Divide your answer in part a by 9.8 to get the mass.