Asked by Bill
As a prank, your friends have kidnapped you in your sleep, and transported you out onto the ice covering a local pond. Since you're an engineer, the first thing you do when you wake up is drill a small hole in the ice and estimate the ice to be 6.7cm thick and the distance to the closest shore to be 30.5 m. The ice is so slippery (i.e. frictionless) that you cannot seem to get yourself moving. You realize that you can use Newton's third law to your advantage, and choose to throw the heaviest thing you have, one boot, in order to get yourself moving. Take your weight to be 588 N. (Lucky for you that, as an engineer, you sleep with your knife in your pocket and your boots on.)
1)(a) What direction should you throw your boot so that you will most quickly reach the shore? away from the closest shore perpendicular to the closest shore straight up in the air at your friend standing on the closest shore
2)(b) If you throw your 1.08-kg boot with an average force of 391 N, and the throw takes 0.576 s (the time interval over which you apply the force), what is the magnitude of the force that the boot exerts on you? (Assume constant acceleration.)
391 N
3)(c) How long does it take you to reach shore, including the short time in which you were throwing the boot?
Just number 3
1)(a) What direction should you throw your boot so that you will most quickly reach the shore? away from the closest shore perpendicular to the closest shore straight up in the air at your friend standing on the closest shore
2)(b) If you throw your 1.08-kg boot with an average force of 391 N, and the throw takes 0.576 s (the time interval over which you apply the force), what is the magnitude of the force that the boot exerts on you? (Assume constant acceleration.)
391 N
3)(c) How long does it take you to reach shore, including the short time in which you were throwing the boot?
Just number 3
Answers
Answered by
R_scott
your mass is ... 588 / g
the force (391 N) accelerates your mass for 0.576 s
find the acceleration ... f = m a ... a = f / m
find the distance during acceleration ... d = 1/2 a t^2
find your final velocity ... v = a t
time to shore = acceleration time +
... {[30.5 m -( acceleration distance)] / (final velocity)}
the force (391 N) accelerates your mass for 0.576 s
find the acceleration ... f = m a ... a = f / m
find the distance during acceleration ... d = 1/2 a t^2
find your final velocity ... v = a t
time to shore = acceleration time +
... {[30.5 m -( acceleration distance)] / (final velocity)}
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