the midpoiint of the diameter (2,3) is the center of the circle.
So the equation is (x-2)^2 + (y-3)^2 = r^2
r is half the length of the diameter, so ...
The diameter of a circle has endpoints at (-2,3) and (6,3). What is an equation of the circle?
2 answers
A(-2, 3), C(x, y), B(6, 3).
x+2 = 1/2(6+2)
X = 2.
y-3 = 1/2(3-3)
Y = 3.
Eq: (x+2)^2+(y-3)^2 = r^2.
x+2 = 1/2(6+2)
X = 2.
y-3 = 1/2(3-3)
Y = 3.
Eq: (x+2)^2+(y-3)^2 = r^2.
2 answers