Asked by Donny
In a bag, the ratio of red to blue counters is 3 : 4. If 3 red counters are removed the ratio of red to blue counters becomes 3 : 5. How many blue counters are there in the bag? *
Answers
Answered by
oobleck
r/b = 2/3, so r = 2/3 b
(r-3)/b = 3/5
5(r-3) = 3b
5(2/3 b - 3) = 3b
now finish solving for b
(r-3)/b = 3/5
5(r-3) = 3b
5(2/3 b - 3) = 3b
now finish solving for b
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