Asked by Anonymous

A rectangular box has a volume of $4320$ cubic inches and a surface area of $1704$ square inches. The sum of the lengths of its $12$ edges is $208$ inches. What would be the volume of the box, in cubic inches, if its length, width and height were each increased by one inch?

Answers

Answered by Reiny
let the original length and width be a, b, and x
abc = 4320
2ab + 2ac + 2bc = 1704 -----> ab + ac + bc = 852
4a + 4b + 4c = 208
a+b+c = 52

new sides: a+1, b+1, c+1
new volume = (a+1)(b+1)(c+1)
= (a+1)(bc + b + c + 1)
= abc + ab + ac + a + bc + b + c + 1
= abc + (ab+ac+bc) + (a+b+c) + 1
= 4320 + 852 + 52 + 1
= .....
Answered by re
sad
Answered by urmom
urmom
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