Asked by help

Factor:
81a^2+5b^2

5 years ago

Answered by Reiny

81a^2+5b^2
= 81a^2 - 5b^2i^2 , where i = √-1, thus i^2 = -1
= (9a + √5 bi)(9a - √5bi)

5 years ago

Answered by Priscilla

14)
An
2
+ 21n + 27 = 7

3 years ago

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