Question

Solve the system of equations. show your work.
x^2-3y^2=13 x-2y=1

Answer 1

from the 2nd: x = 2y + 1
sub that into the 1st
(2y+1)^2 - 3y^2 = 13
4y^2 + 4y + 1 - 3y^2 - 13 = 0
y^2 + 4y - 12 = 0

it factors very nicely, and you will two values of y
sub each into x = 2y+1 to get their corresponding x values

Answer 2

Thank you!! So much!