A. (1 - 1/3)^3
B. "at least one" means not none ... 1 - (A. result)
C. 3C1 * 1/3 * (2/3)^2
the probability of a seed germinating is 1/3.If three of the seeds are planted,what is the probability that:A.none germinates B.at least one will germinate C.only one will germinate.
2 answers
binomial probability
A=p(germinate)=1/3
B=or(not germinate)=3/3-1/3=2/3
We have
1 3 3 1
(A+B)³=A³+3A²B+3AB²+B³
(A)=(2/3)³=8/27
B=[1-A]=[27-8]/27=19/27
C=3AB²=3(1/3)(4/9)=4/9
A=p(germinate)=1/3
B=or(not germinate)=3/3-1/3=2/3
We have
1 3 3 1
(A+B)³=A³+3A²B+3AB²+B³
(A)=(2/3)³=8/27
B=[1-A]=[27-8]/27=19/27
C=3AB²=3(1/3)(4/9)=4/9