Question

Find out the amount of heat required to convert 1 gm of ice at -30 ⁰C to 1 gm of steam at 120
⁰C. Given the specific heat of ice is 2090 J/kg/⁰C, specific heat of water 4180 J/kg/⁰C, specific heat
of steam is 2010 J/kg/⁰C, latent heat of ice to water is 333000 J/kg and latent heat of water to steam
is 2260000 J/kg.

Answer 1

q1 = heat to change T ice from -30 to zero.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial) = ? where Tfinal is zero and Tinitial is -30.
q2 = heat to melt ice @ zero to liquid @ zero.
q2 = mass ice x heat fusion = ?
q3 = heat to change T from zero C to 100 C.
q3 = mass water x specific heat H2O x (Tfinal-Tinitial) = ?
q4 = heat to convert water @ 100 C to steam @ 100 C.
q4 = mass water x heat vaporization = ?
q5 = heat to change T of steam from 100 to 120 C.
q5 = mass steam x specific heat steam x (Tfinal-Tinitial) = ?
qtotal = q1 + q2 + q3 + q4 + q5 = ?
Post your work if you get stuck.

Answer 2

Find out the amount of heat required to convert 1 gm of ice at -30 ⁰C to 1 gm of steam at 120
⁰C. Given the specific heat of ice is 2090 J/kg/⁰C, specific heat of water 4180 J/kg/⁰C, specific heat
of steam is 2010 J/kg/⁰C, latent heat of ice to water is 333000 J/kg and latent heat of water to steam
is 2260000 J/kg.
Plz solve it....